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Problem 2.
We are given an acute triangle $ABC$. Let $D$ be the point on its circumcircle such that $AD$ is a diameter. Suppose that points $K$ and $L$ lie on segments $AB$ and $AC$, respectively, and that $DK$ and $DL$ are tangent to circle $AKL$.
Show that line $KL$ passes through the orthocenter of triangle $ABC$.
Solution
Let $H$ be the orthocenter of $ABC$, and let $M$ be the midpoint of $\overline{KL}$. Notice that \[\angle DBK=\angle DMK=\angle DCL=\angle DML=90^\circ,\]so $BDMK$ and $CDML$ are cyclic. We have \[\angle ABM=\angle KDM=90^\circ-\angle DKM=90^\circ-\angle BAC=\angle ABH,\]and similarly, $\angle ACM=\angle ACH$. This means $M=H$, so $H$ lies on $\overline{KL}$, as desired..
 
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